Matrices — Mathematics Class 12 Notes (CBSE & HBSE)
Free NCERT Mathematics notes for Matrices (Class 12) on Siksha Sarovar, aligned to CBSE and Haryana Board (HBSE). This chapter is broken into 3 topics with clear explanations, formulas, solved examples and board-pattern practice — free to read, no sign-up required.
Board exam focus — Matrices (CBSE & HBSE)
Matrices carries 8-10 marks in CBSE and HBSE. Questions span operations (addition, multiplication), transpose, symmetric/skew-symmetric decomposition, elementary operations, and finding inverse using elementary row operations.
Types of Matrices and Matrix Operations
Types of Matrices
| Type | Definition |
|---|---|
| Row matrix | Only 1 row: [a₁ a₂ … aₙ] |
| Column matrix | Only 1 column |
| Square matrix | m = n (rows = columns) |
| Zero/Null matrix | All entries = 0 |
| Identity matrix (I) | Square, diagonal entries = 1, others = 0 |
| Diagonal matrix | Non-zero entries only on main diagonal |
| Scalar matrix | Diagonal matrix with all diagonal entries equal |
| Upper triangular | aᵢⱼ = 0 for i > j |
| Lower triangular | aᵢⱼ = 0 for i < j |
Matrix Addition
For A and B of same order m×n: (A+B)ᵢⱼ = aᵢⱼ + bᵢⱼ
Properties:
- A+B = B+A (commutative)
- (A+B)+C = A+(B+C) (associative)
- A+O = O+A = A (O is additive identity)
- A+(−A) = O (additive inverse)
Scalar Multiplication
(kA)ᵢⱼ = k·aᵢⱼ
Matrix Multiplication
For A of order m×n and B of order n×p, AB exists and is m×p.
(AB)ᵢⱼ = Σₖ aᵢₖ · bₖⱼ (sum over k from 1 to n)
Properties of Matrix Multiplication:
- In general, AB ≠ BA (NOT commutative)
- (AB)C = A(BC) (associative)
- A(B+C) = AB+AC (distributive)
- AI = IA = A (I is multiplicative identity)
- AB = 0 does NOT necessarily mean A = 0 or B = 0
Order compatibility rule: For AB to exist, columns of A = rows of B. If A is m×n and B is n×p, then AB is m×p.
CBSE Tip: Always check the order before multiplying. The product AB has the same number of rows as A and same number of columns as B.
Transpose, Symmetric and Skew-Symmetric Matrices
Transpose of a Matrix
The transpose A' (or Aᵀ) of an m×n matrix A is obtained by interchanging rows and columns. (A')ᵢⱼ = Aⱼᵢ
Properties of Transpose:
- (A')' = A
- (kA)' = kA'
- (A+B)' = A'+B'
- (AB)' = B'A' (order reverses!)
Symmetric Matrix
A square matrix A is symmetric iff A' = A ⟺ aᵢⱼ = aⱼᵢ for all i, j
Example: A = [[1,2,3],[2,4,5],[3,5,6]] is symmetric.
Skew-Symmetric Matrix
A square matrix A is skew-symmetric iff A' = −A ⟺ aᵢⱼ = −aⱼᵢ for all i, j
Key result: The diagonal entries of a skew-symmetric matrix are all zero (since aᵢᵢ = −aᵢᵢ ⟹ 2aᵢᵢ = 0).
Decomposition Theorem
Every square matrix A can be written as: A = (1/2)(A+A') + (1/2)(A−A')
where (1/2)(A+A') is symmetric and (1/2)(A−A') is skew-symmetric.
Results on Symmetric Matrices
- If A is symmetric, A+A' = 2A (symmetric), A−A' = O
- If A and B are symmetric: A+B is symmetric; AB is symmetric iff AB = BA
- AA' and A'A are always symmetric
CBSE Tip: To show a matrix is symmetric, compute A' and verify A' = A. To decompose a matrix, always use the formula A = P + Q where P = (A+A')/2 and Q = (A−A')/2.
Elementary Row Operations and Finding Inverse
Elementary Row Operations
Three types of elementary row operations (ERO) on a matrix:
- Rᵢ ↔ Rⱼ — interchange rows i and j
- Rᵢ → kRᵢ — multiply row i by non-zero scalar k
- Rᵢ → Rᵢ + kRⱼ — add k times row j to row i
Finding A⁻¹ by Elementary Row Operations
Method: Write [A | I] and apply EROs to convert A to I. The same EROs convert I to A⁻¹.
Existence Condition: A⁻¹ exists iff |A| ≠ 0 (A is non-singular).
Step-by-step process:
- Write the augmented matrix [A | I]
- Apply EROs to reduce A to I
- The right part becomes A⁻¹
Example: Find A⁻¹ for A = [[2,1],[5,3]]
- [A|I] = [[2,1,1,0],[5,3,0,1]]
- R₂ → R₂ − (5/2)R₁: [[2,1,1,0],[0,1/2,−5/2,1]]
- R₂ → 2R₂: [[2,1,1,0],[0,1,−5,2]]
- R₁ → R₁ − R₂: [[2,0,6,−2],[0,1,−5,2]]
- R₁ → R₁/2: [[1,0,3,−1],[0,1,−5,2]]
- ∴ A⁻¹ = [[3,−1],[−5,2]]
Verify: AA⁻¹ = [[2·3+1·(−5), 2·(−1)+1·2],[5·3+3·(−5), 5·(−1)+3·2]] = [[1,0],[0,1]] ✓
Properties of Invertible Matrices
- (A⁻¹)⁻¹ = A
- (AB)⁻¹ = B⁻¹A⁻¹
- (A')⁻¹ = (A⁻¹)'
- (kA)⁻¹ = (1/k)A⁻¹
CBSE Tip: For 2×2 matrix [[a,b],[c,d]], A⁻¹ = (1/|A|)[[d,−b],[−c,a]]. This is a quick formula. For 3×3, use ERO or adjoint method.
Frequently asked questions
Are these Matrices notes free?
Yes — the Matrices notes for Mathematics (Class 12) on Siksha Sarovar are completely free to read, with no account required.
Do these notes follow CBSE and HBSE?
Yes. The Matrices notes are NCERT-aligned and include guidance for both CBSE and Haryana Board (HBSE), with important questions and MCQs for revision.
What does the Matrices chapter cover?
Concept explanations, key formulas and definitions, fully solved examples and board-pattern practice questions for Matrices.