Siksha Sarovar

Siksha Sarovar (sikshasarovar.com) is a free educational web application that helps students in India learn programming and prepare for academic and competitive exams. The platform offers structured coding courses (C, C++, Python, Java, HTML, CSS, PHP, Power BI, AI, Machine Learning, Data Science), complete university curriculum notes for BCA/MCA students with previous year question papers, Class 10 and Class 12 CBSE/HBSE school notes, and dedicated preparation material for SSC, UPSC, Banking, Railway and other government exams. Browsing the site is completely free and requires no account. Users may optionally sign in with Google solely to save their learning progress, quiz scores and personal preferences across devices.

Privacy Policy | Terms of Service | Contact Siksha Sarovar | About Siksha Sarovar

v4.0.9 · PWA
Siksha Sarovar logo
Siksha Sarovar
Your Learning Universe

Siksha Sarovar is a free e-learning platform for coding courses, BCA university notes and competitive exam preparation. Optional Google sign-in saves your learning progress across devices.

Initializing knowledge base…
Compiling modules 0%

Continuous Probability Distributions

Lesson 5 of 11 in the free Probability and Statistics- BCA-DS-23-204 notes on Siksha Sarovar, written by Rohit Jangra.

5. Continuous Probability Distributions

1. Uniform Distribution

  • Use: Every value in a range is equally likely.
  • Example (Random Number Generator):
  • A computer generates a random number $X$ between 0 and 10.
  • Question: Probability the number is less than 3?
  • Range width = 10. Target width = 3.
  • Calculation:
  • $$ P(0 < X < 3) = \frac{\text{Target Width}}{\text{Total Width}} = \frac{3}{10} = 0.3 $$

2. Exponential Distribution

  • Use: Time until an event happens (e.g., failure of a machine, arrival of a bus).
  • Example (Battery Life):
  • The average life of a battery is 10 hours. Rate $\lambda = 1/10 = 0.1$.
  • Question: Probability the battery lasts less than 5 hours?
  • Calculation: CDF Formula for Exponential is $F(x) = 1 - e^{-\lambda x}$.
  • $$ P(X < 5) = 1 - e^{-0.1(5)} $$ $$ P(X < 5) = 1 - e^{-0.5} \approx 1 - 0.606 = 0.394 $$ (39.4% chance the battery dies before 5 hours).

3. Normal Distribution

  • Use: Bell curve. Natural phenomena (height, IQ, errors).
  • Example (Student Heights):
  • Average height ($\mu$) = 170 cm. Standard Deviation ($\sigma$) = 10 cm.
  • Question: What is the probability a student is shorter than 160 cm?
  • Step 1: Find Z-score.
  • $$ Z = \frac{X - \mu}{\sigma} = \frac{160 - 170}{10} = \frac{-10}{10} = -1 $$

  • Step 2: Look up Z-table or use rule.
  • Z = -1 means the value is 1 standard deviation below the mean.
  • According to the Empirical Rule (68-95-99.7 rule), roughly 68% of data is within $\pm 1\sigma$.
  • This leaves 32% in the tails.
  • Since the curve is symmetric, the lower tail (below -1) is roughly $32\% / 2 = 16\%$.
  • Result: Probability is approximately 0.16 (or 16%).